Zip Python | S3 'link' Download Multiple Files As

This approach reads each S3 object into a memory buffer, zips them, and can either return the ZIP to a user or upload it back to another S3 bucket.

Use a library like stream-zip on PyPI to start returning compressed data before all files are even retrieved. s3 download multiple files as zip python

Ideal for AWS Lambda functions where disk space is limited. This approach reads each S3 object into a

Constrained by the available RAM; very large files may trigger "out of memory" errors. Method 2: Streaming Large Files (Memory Efficient) Constrained by the available RAM; very large files

For handling larger datasets without filling up memory, you can use . By using the smart-open library or iter_chunks , you can pipe data from S3 directly into a ZIP archive.

import boto3 import zipfile import io def create_s3_zip(bucket_name, file_keys): s3 = boto3.client('s3') zip_buffer = io.BytesIO() with zipfile.ZipFile(zip_buffer, 'w', zipfile.ZIP_DEFLATED) as zipf: for key in file_keys: # Download object into memory response = s3.get_object(Bucket=bucket_name, Key=key) content = response['Body'].read() # Add file to ZIP archive zipf.writestr(key.split('/')[-1], content) zip_buffer.seek(0) return zip_buffer # Ready for download or upload Use code with caution.

To download multiple files from Amazon S3 as a ZIP file using Python, you must use a compute resource (like EC2 or AWS Lambda) to perform the compression, as S3 is a storage-only service. The most efficient method for small to medium tasks is an , which avoids writing to local disk by using Python's io.BytesIO and zipfile modules. Method 1: In-Memory ZIP Creation (Best for Lambda)